#include<iostream>
using namespace std;
typedef long long ll;
double n,m,t;
int main(){
    cin >> t;
    while(t--)
    {
        double max,min;
        scanf("%lf %lf %lf %lf",&n,&max,&min,&m);
        double ans=n*m;

        double k=max*(n-1)+min;
        double l=min*(n-1)+max;
        if(min>max){
            cout << "no" << endl;
            continue;
        }
        if(ans>=l && ans<=k)cout << "yes" <<endl;
        else cout << "no" <<endl;



    }

    return 0;
}