#include<stdio.h>
double fun1(double n)
{
    return (46-38.0/n)/(19-11.0/n); 
}
double fun2(double n)
{
    return 1+(n-2)*(19.0/27.0);
}
int main()
{
    int aaa;
    int T,k=0;
    double n;
    scanf("%d",&T);
    while(T--)
    {
        scanf("%lf",&n);
        printf("Case #%d:\n",++k);
        printf("%.6lf %.6lf\n",fun2(n),fun1(n));
    }
}