#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
#define maxn 200007
#define infm ((1<<30)-1)
#define fst first
#define scn second

using namespace std;


typedef pair<double,double> PAf;
typedef pair<int,int> PA;
typedef long long LL;
typedef pair<int,PA> TA;

int n,m,ans,tot;
const int p=1000000007;

LL qpow(LL a,LL b)
{
    LL ans;
    for(ans=1;b;b>>=1,a=a*a%p)
        if(b&1)ans=ans*a%p;
    return ans;
}
LL getc(LL n,LL m)
{
    if(n<m)return 0;
    if(m>n-m)m=n-m;
    LL s1=1,s2=1;
    for(LL i=0;i<m;i++)
    {
        s1=s1*(n-i)%p;
        s2=s2*(i+1)%p;
    }
    return s1*qpow(s2,p-2)%p;
}

LL fact[maxn];

void extgcd(LL a, LL b, LL &x, LL &y)
{
    if (b != 0) {
        extgcd(b, a % b, y, x);
        y -= (a / b) * x;
    }
    else {
        x = 1;
        y = 0;
    }
}
const int modp=p;
LL mod_inv(LL a)
{
    LL x, y;
    extgcd(a, modp, x, y);
    return (modp + x % modp) % modp;
}

LL mod_fact(LL n, LL p, LL& e) {
    e=0;
    if (n==0) return 1;
    LL res=mod_fact(n/p,p,e);
    e+=n/p;
    if (n/p%2!=0) return res*(p-fact[n%p])%p;
    return res*fact[n%p]%p;
}

LL lucas(LL n,LL k)
{
    if (n<0||k<0||n<k) return 0;
    LL e1,e2,e3;
    LL a1=mod_fact(n,p,e1), a2=mod_fact(k,p,e2), a3=mod_fact(n-k,p,e3);
    if (e1>e2+e3) return 0;
    return a1*mod_inv(a2*a3%p)%p;

}

int q[maxn];

int main()
{
    int T=1;
    scanf("%d",&T);
    for (int cT=1;cT<=T;++cT)
    {
        tot=0;
        int k;
        scanf("%d%d%d",&n,&m,&k);
        for (int i=0;i<n;++i) {
            int x;
            scanf("%d",&x);
            q[i]=x;
        }
        int tmp=0,l,r;
        for (int i=0;i<n;++i) {
            if (q[i]>=m) ++tmp;
            r=i;
            if (tmp==k) {
                break;
            }
            ++r;
        }
        LL ans=n-r;
        for (int i=1;i<n;++i) {
            if (q[i-1]>=m) --tmp;
            while (r+1<n&&tmp<k) {
                ++r;
                if (q[r]>=m) ++tmp;
            }
            if (tmp>=k) ans+=n-r;
        }
        cout<<ans<<endl;
    }
    return 0;
}