#include using namespace std; int n,m; long long ans; void solve(){ scanf("%d%d",&n,&m); if(m*2>n)m=n/2; ans=1ll*m*(2*n-2*m-1); printf("%lld\n",ans); } int main(){ int t;scanf("%d",&t); for(;t;--t)solve(); return 0; }