#include using namespace std; const int maxn = 1e6 + 10; typedef long long ll; ll sum[maxn]; void init() { for (int i = 1; i < maxn; i++) { sum[i] += sum[i-1] + i; } } int main() { int t; cin >> t; init(); while (t--) { int n, m; cin >> n >> m; if (m >= n/2) { cout << 1LL*n*(n-1)/2 << endl; } else { cout << sum[n-1] - sum[n-1-m*2] << endl; } } }